Two objects are moving along separate linear paths where each path is described by postion, d, and time, t. the variable d is measured in meters and the variable t is measured in seconds. the equation describing the graph of the postion of the first object with respect to time is d=2.5t+2.2. the graph of the the position of the second object is a parallel line passing through (t=0,d=1). what is the equation of the second graph.
a) d=2.5t+1
b) d=-0.4t+1
c) d=2.5t+3.2

Linear equation:  d = m t + b

If the graph of the position of the second object is parallel to d = 2.5 t +2.2, than m = 2.5

t = 0, d = 1

1 = 2.5 · 0 + b

b = 1

A ) d = 2.5 t + 1

Also correct on Plato :) , just scored a 100%

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

answer: approximately 206 bones

i hope this u out a branlist and a would be greatly appreciated :