Mathematics, 06.05.2020 00:14 viuygoiu6446
Y= 4*x^2-32-20-16 pa= (x*SQRT(2)+a+b)/2 pb= (x*SQRT(2)+a+c)/2 pc= (x*SQRT(2)+d+c)/2 pd= (x*SQRT(2)+d+b)/2 pe= (x*(2)+c+b)/2 pf= (x*(2)+a+d)/2 SQRT(pa*(pa-a)*(pa-b)*(pa-x*SQRT(2) ))+x^2/2=32 SQRT(pb*(pb-a)*(pb-c)*(pb-x*SQRT(2) ))+x^2/2=20 SQRT(pc*(pc-d)*(pc-c)*(pc-x*SQRT(2) ))+x^2/2=16 SQRT(pc*(pc-d)*(pc-c)*(pc-x*SQRT(2) ))+x^2/2=y SQRT(pe*(pe-c)*(pe-b)*(pe-x*(2)))+2 *x^2+20+16=4*x^2 SQRT(pf*(pf-d)*(pf-a)*(pf-x*(2)))+2 *x^2=4*x^2
Answers: 2
Another question on Mathematics
Mathematics, 21.06.2019 16:30
What is the difference between regular convex and concave polygons
Answers: 1
Mathematics, 21.06.2019 21:00
Tim open up a new saving account with a $50 deposit and plant to deposit $20 per week into the same account.write an expression to represent the total amount in his savings account.
Answers: 1
Mathematics, 22.06.2019 00:30
How can you find the magnitude of a vector, v = < x,y > , where the horizontal change is x and the vertical change is y?
Answers: 1
You know the right answer?
Y= 4*x^2-32-20-16 pa= (x*SQRT(2)+a+b)/2 pb= (x*SQRT(2)+a+c)/2 pc= (x*SQRT(2)+d+c)/2 pd= (x*SQRT(2)+d...
Questions
English, 21.04.2020 19:20
Mathematics, 21.04.2020 19:20
Mathematics, 21.04.2020 19:20
Medicine, 21.04.2020 19:20
History, 21.04.2020 19:20
Mathematics, 21.04.2020 19:20
Biology, 21.04.2020 19:20
English, 21.04.2020 19:20
English, 21.04.2020 19:20
Social Studies, 21.04.2020 19:20
