You throw your ball into the air from a height of 4.2 feet with an initial vertical velocity of 24 feet per second. Use the vertical motion model, h = - 16t ^ 2 + vt + s , where v is the initial velocity in feet per second and s is the height in feet , to calculate the maximum height of the ball. Round your answer to the nearest tenth if necessary . Maximum height : feet

Use the equation h(t)=-b/2a to find the x value of the vertex, then plug that back into the equation to find the y value which is your height.

Step-by-step explanation:

You can also complete the square to get the equation into vertex form, then your height is the y value of your vertex. Remember the maximum height is always at the vertex of an inverted parabola.

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.