In the function f(x)=(x-2)^2+4, the minimum value occurs when x is

A.)-2
B.)2
C.)-4
D.)4

ou would have 12 of each

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x

(-5,-28)

i graphed to on desmos.