Suppose you flip a coin and spin a spinner that is divided into 8 equal regions. Of the 8 equal regions, 3 are red, 4 are black and 1 green. What is the probability of "tails" on the coin, and the spinner landing on red? (Hint: How many spaces are on the spinner total?)Immersive Reader
(5 Points)

18.75%

Step-by-step explanation:

The probability of the coin is 1/2, because it only has two options (tail or head).

Now, in the case of roulette, it has a total of 8 options, and the red region has 3 parts, that is, of the 8 options, roulette 3 is red, therefore the probability is 3/8

Now the final probability is the multiplication of the probability of both events:

(1/2) * (3/8) = 0.1875 s 18.75%

In other words, the probability of these two events happening, that the tail comes out and is red, i

the camry sales+accord sale=828,000. to make it so the two numbers are 18 thousand apart and still equal 828,000, you first need to find out what half of 828,000 is. 828,000/2=414,000. for the two numbers to equal 828,000, you have to add the same amount as you subtract from the middle. in this case, the number is 9,000 because it's half of 18,000. to equal 828,000, you have to add 9,000 to 414,000 for the camry and subtract 9,000 from 414,000 for the accord. 414,000+9,000=423,000.

414,000-9,000=405,000.

423,000+405,000=828,000.

423,000-405,000=18,

hope it