Mathematics, 05.05.2020 20:21 gallegosarmanni

Answer needed asap!! Graph a line with a slope of 3/4 that contains the point (2,-3)

Answers: 2

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Answer from: cynthiafchs9203

The graph of the given line is required.

The required graph is attached below.

The slope of the line is $m=\dfrac{3}{4}$

The point is (2,-3)

The equation is

$y-(-3)=\dfrac{3}{4}(x-2)\\\Rightarrow y+3=\dfrac{3}{4}x-\dfrac{3}{2}\\\Rightarrow y=\dfrac{3}{4}x-\dfrac{9}{2}$

Finding another point

x=0

$y=0-\dfrac{9}{2}$

$(0,-\dfrac{9}{2})$

Join the two points and the graph is drawn.

Learn more:

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Answer from: twinkie7078

By graphing the line, we have the equation y = $\frac{3}{4} x -4.5$

Step-by-step explanation:

What this question is asking us is to find the equation of the line with the value of the slope given in the question and also passing through the point in the question

For a straight line, the general equation can be represented as

y = mx + c

where m is the slope of the line and c is the y intercept. From the question, we have the value of the slope, what we have left to find is the value of the intercept. We find this by inserting the x, y and the slope value into the general equation of a straight line.

We have;

-3 = 3/4(2) + c

c = -3 - 6/4

c = -3-1.5 = -4.5

Thus, the equation of the line is;

y = $\frac{3}{4} x -4.5$

Answer needed asap!! Graph a line with a slope of 3/4 that contains the point (2,-3)

Answer from: Quest

$a_1 = 1$ , and

$a_{n+1} = a_n + (n + 1)$ for $n \ge 1$

step-by-step explanation:

we can analyze the pattern at which the terms increase. let us denote $a_1 = 1$ , $a_2 = 3$ , $a_3 = 6$ , so that we can call

1 the 1st term, 3 the 2nd term, 6 the 3rd term,etc.

note the following:

from the 1st term (1) to the 2nd term (3), we go up by 2,from the 2nd term (3) to the 3rd term (6), we go up by 3from the 3rd term (6) to the 4th term (10), we go up by 4, andfrom the 4th term (10) to the 5th term (15), we go up by 5.

the pattern: to get the next term value, we just add the next term number (e.g. 1st, 2nd, to the previous term value (term values are the given numbers in the question, 1, 3, 6, 10, 15,

from $a_1 = 1$ , to get to $a_2 = 3$ , we add $2(=1+1)$

from $a_2 = 3$ , to get to $a_3 = 6$ , we add $3 (=2+1)$

etc.

we need to form a recursive formula, a formula that has the next term as a function of the previous term. so a possible recursive formula can be

$a_1 = 1$ , and $a_{n+1} = a_n +(n + 1)$ for $n \ge 1$

Answer from: Quest

what statement? is there an image?

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Answer needed asap!! Graph a line with a slope of 3/4 that contains the point (2,-3)...

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