A bale of hay in the shape of a rectangular prism has a length of 4 feet, a width of 2 feet, and a height of 2 feet. A cylindrical bale of hay has a diameter of 4 feet and a height of 6 feet. How many rectangular bales contain the same amount of hay as one cylindrical bale? Round your answer to the nearest tenth.

About 4.7

Step-by-step explanation:

First Find the volume of the cylindrical bale.

V= π(r)^2*6

V=π(2)^2*6

V=π*4*6

V=π24

The answer is about 75.4

Now find the volume of the Rectangular Prism

V= w*h*l

V= 2*2*4

The answer is 16

Finally divide 75.4÷16 Which to the nearest tenth is 4.7.

p.s please correct me if I am wrong.

step-by-step explanation:

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(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0