The amount of Jen's monthly phone bill is normally distributed with a mean of $59 and a standard deviation of $10. What percentage of her phone bills are between $29 and $89?

And we can find this probability with this difference:

And in order to find these probabilities using the normal standard distribution or excel and we got.  

So we expect about 99.735% of values between $29 and $89

Step-by-step explanation:

Let X the random variable that represent the amount of Jens monthly phone of a population, and for this case we know the distribution for X is given by:

Where and

We are interested on this probability first in order to find a %

The z score is given by:

If we apply this formula to our probability we got this:

And we can find this probability with this difference:

And in order to find these probabilities using the normal standard distribution or excel and we got.  

So we expect about 99.735% of values between $29 and $89

a

step-by-step explanation:

given the 2 equations

- x + y = - 2 → (1)

2x - 3y = 4 → (2)

multiplying (1) by 2 and adding to (2) will eliminate the x- term

- 2x + 2y = - 4 → (3)

add (2) and (3) term by term

(2x - 2x) + (- 3y + 2y) = (4 - 4), simplifying gives

- y = 0 ⇒ y = 0

substitute y = 0 in either of the 2 equations for corresponding value of x

substituting in (2) gives

2x = 4 ( divide both sides by 2 )

x = 2

solution is (2, 0 ) → a

answer is  

minor arc – sw

major arc – stu

semicircle – wst

i got it down chief.