In simplest radical form, what are the solutions to the quadratic equation 6=x^2-10x?

and

Step-by-step explanation:

First move everything to the same side:

--->

Then use the quadratic formula:

x= (-b ± )/2a

x= (-(-10) ± )/2*1

x= (10 ± )/2

Solution 1:

(10 + )/2

=

Solution 1:

(10 - )/2

=

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a

jml angle lkj & angle mj = lm