A lomy owner has his own fuel supply and needs to refill his storage tank. He has just completely

filled the fuel tank of the lorry with 170 litres from empty. He now has 100 litres of fuel left in his

storage tank. With the price of fuel expected to fall soon he only wants to buy enough for the next

fortnight. Normally his regular short daily trips total 300 km and this leaves just 20 litres in the

lorry's fuel tank. He expects to complete three regular days of 300 km journeys each week, but

this could rise to five. Sometimes the total journeys are longer but his daily trips never total more

than 400 km in a day. He never works more than five days in a week. His storage container holds

4000 litres

How much fuel should he order to be certain that he has enough for the next two weeks?

He should order for 1046.67 litres fuel to be certain that he has enough for the next two weeks

Step-by-step explanation:

Note that he has just completely

filled the fuel tank of the lorry with 170 litres from empty. He now has 100 litres of fuel left in his storage tank

If his regular short daily trips total 300 km and this leaves just 20 litres in the lorry's fuel tank.

That is 100 litres -20 litres = 80 litres

On 300km, he consumed 80 litres

He plans to complete three regular days of 300 km journeys each week, but this could rise to five. Sometimes the total journeys are longer but his daily trips never total more than 400 km in a day. He never works more than five days in a week. His storage container holds

4000 litres

From all these analysis, we can deduce that the maximum km of journey he should prepare for is

400km × 5 = 2000km for one week

Since he consumed 80 litres of fuel for any 300km

Then,

80/300 = L/2000

L = 1600/3

L = 533.33 litres

The journey for two weeks will be

533.33 × 2 = 1066.67 litres

Recall that he left 20 litres in the tank. Take this away from 1066.67 litres.

1066.67 - 20 = 1046.67 litres

He should therefore order for 1046.67 litres fuel to be certain that he has enough for the next two weeks

answer: get jesus in your life

step-by-step explanation:

la parábola es el lugar

geométrico en el cual los puntos tienen una distancia idéntica, equidistantes,

de un punto denominado foco, f, y una recta denominada directriz

el radio vector de una

parábola es el segmento que existe entre un punto cualquiera y el foco.

por la ecuación se observa

que la parábola abre hacia la derecha, por lo cual podemos usar las siguientes fórmulas

la ecuación ordinaria de la

parábola es y^2 = 4px, donde p es la longitud desde el vértice de la parábola al

foco.

la fórmula de la directriz

es x + p = 0

resolviendo:

y^2-9x = 0

y^2 = 9x

4p = 9, entonces p = 9/4

entonces el foco tendrá la

coordenada f(9/4,0)

la directriz vendrá

expresada por

x + p = 0

x = -p

x = -9/4

el problema indica que la

ordenada es igual a 6, entonces

(6)^2=9x

x = 36/9

x = 4

entonces el punto al cual

hay que obtener la distancia será p(4,6)

calculando se tendrá: pf = 

pf = 6,25 u

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step-by-step explanation: