If anyone is good at math and knows how to do this problem please answer. I will give more points

1, 5, 13, 29, 61

Step-by-step explanation:

2^(n+1) - 3

n = 1

2^(1+1) - 3

2² - 3

4 - 3

1

n = 2

2^(2+1) - 3

2³ - 3

8 - 3

5

n = 3

2^(3+1) - 3

2³ - 3

16 - 3

13

n = 4

2^(4+1) - 3

2⁵ - 3

32 - 3

29

n = 5

2^(5+1) - 3

2⁶ - 3

64 - 3

61

the answer is simply just 6n add the two together as they have an n

he has now walked a total of what?

if i know what this is maybe i can

step-by-step explanation: