16, 10, 5, 7, 13

Based on your sample, what is the average age of the porcupines? What is the standard deviation? Round your

answers to the nearest tenth.

Mean = 10.2

Standard deviation = 4.0

Step-by-step explanation:

The average age = mean age

Mean = (16 + 10 + 5 + 7 + 13)/5

Mean = 51/5 = 10.2

What is the standard deviation will be square root of variance

(16 - 10.2) + (10 -10.2) + (5-10.2) + (7-10.2)+( 13-10.2)

5.8 + 0.2 -5.2 - 3.2 + 2.8

Square each number

33.64 + 0.04 + 27.04 + 10.24 + 7.84

Variance = 78.8/5 = 15.76

Standard deviation = 3.969 = 4.0

Step-by-step explanation:

Mean = sum of the items in the sample/number of items in the sample

Number of items(ages) = 5

Sum of ages = 16 + 10 + 5 + 7 + 13 = 51

Mean = 51/5 = 10.2

Standard deviation = √(summation(x - mean)/n

Summation(x - mean) = (16 - 10.2)^2 + (10 - 10.2)^2 + (5 - 10.2)^2 + (7 - 10.2)^2 + (13 - 10.2)^2 = 78.8

Standard deviation = √78.8/5

Standard deviation = 4.0 rounded to the nearest tenth

the answer is 99.