1. If the function fx=x2-2x-15 has roots at the points (-3, 0) and 5, 0, what is the vertex of the function? **

  (1, -16)

Step-by-step explanation:

The line of symmetry is halfway between the x-intercepts, at ...

  x = (-3 +5)/2 = 1

The line of symmetry goes through the vertex, so to find the y-coordinate of the vertex, we need to find f(1):

  f(1) = 1^2 -2(1) -15 = -16

The vertex of the function is (x, y) = (1, -16).

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hello from mrbilldoesmath!

answer:   x (x+6)^2, choice b

discussion:

factor x out of the equation:

x^3 + 12x^2 + 36x = x (x^2 + 12x + 36).

note that 6+6 = 12 and 6*6 = 36 so the above factors into:

x (x+6)^2

which is choice b

you,

mrb