The box plots show the weights, in pounds, of the dogs in two different animal shelters.
Weights of Dogs in Shelter A
6
8
10
12
14
16
18
20
22
24
26
28
Weights of Dogs in Shelter B
Which is true of the data in the box plots? Select three choices.

Question:

1) The median weight for shelter A is greater than that for shelter B.

2)The median weight for shelter B is greater than that for shelter A.

3) The data for shelter A are a symmetric data set.

4) The data for shelter B are a symmetric data set.

5) The interquartile range of shelter A is greater than the interquartile range of shelter B.

The correct options are;

1) The median for shelter A is greater than that for shelter B

4) The data for shelter B are a symmetric data set

5)The interquartile range for shelter A is greater than the interquartile range for shelter B

Step-by-step explanation:

Here we have weight of dogs in Shelter A

Min = 8

Max = 30

Lower interquartile = 17

Upper inter quartile = 28

Interquartile range = 28 - 17 = 9

Median = 21

For the dogs in shelter B

Min = 10

Max = 28

Lower interquartile = 16

Upper inter quartile = 20

Interquartile range = 20 - 16 = 4

Median = 18

Therefore, the median for shelter A is greater than that for shelter B

The data for shelter B are a symmetric data set

The interquartile range for shelter A is greater than the interquartile range for shelter B.

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

y > 1/3x

y < = -x + 4

hope this : )