Question:
△MNO has vertices M(8,−2), N(−15,−20) and O(−14,19). Which of the following represents the translation of △MNO along vector <7,−2> and its reflection across the y-axis?

M (8, −2) → M ′(1, 0) → M ″(1, 0);
N (−15, −20) → N ′(−22, −18) → N ″(−22, 18);
O (−14, 19) → O ′(−21, 21) → O ″(−21, 21)

M (8, −2) → M ′(1, 0) → M ″(−1, 0);
N (−15, −20) → N ′(−22, −18) → N ″(22, −18);
O (−14, 19) → O ′(−21, 21) → O ″(21, −21)

M (8, −2) → M ′(15, −4) → M ″(−15, −4);
N (−15, −20) → N ′(−8, −22) → N ″(8, −22);
O (−14, 19) → O ′(−7, 17) → O ″(7, 17)

M (8, −2) → M ′(1, 0) → M ″(1, 0);
N (−15, −20) → N ′(−8, −22) → N ″(−8, 22);
O (−14, 19) → O ′(−7, 17) → O ″(−7, −17)

the entire expression should be subtracted from 30. to subtract the quantity, distribute the negative sign, which changes the signs on the terms. so, the –2 changes to positive and gets added to 30 instead of subtracted from it.

hope this ! ^w^

the answer is a i belaeve atleast thats what my calculator just gfave me

step-by-step explanation:

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation:

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step-by-step explanation:

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