A bicycle lock requires a two-digit code of numbers 1 through 9, and any digit may be used only once. Which
expression would determine the probability that both digits are even?
P(both even) = (P1) (3P :)
P(both even) = 6(1)(61)
P(both even) = (sPr) GPa)
P(both even) = GC1GC)
Intro
Done