Y=-x^2 + 4
y = 2x + 1

Solve systems of equations and show work

y = -x^2 + 4  

y = 2x + 1  

Subtract the bottom equation from the top .  

0 = -x^2 - 2x + 3  

x^2 + 2x - 3 = 0  

Factor  

( x + 3)(x - 1) = 0  

x = -3  & x = 1  

When x = -3  

y = -(-3)^2 + 4  

y = -9 + 4  

y = -5  

&  

When x = 1  

y = -(1)^2 + 4  

y = -1 + 4  

y = 3

Step-by-step explanation:

The answers are

(1,3) (-3,-5)

Sovle by substitution. Plug in y.

x^2+4=2x+1

-4 -4

x^2=2x-3

2

1,3

Repeat with x

-3,-5

12m

step-by-step explanation:

square root means have of a number so have of 3 is 1.5 then multiply it by 8 and you get your answer!

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph