The length of a rectangular garden is 7 feet longer than its width. If the garden’s perimeter is 178 feet what is the area of the garden in square feet.

1968ft^2

Step-by-step explanation:

Perimeter(p)=178feet

P=2L+2w

178=2L+2w

178=2(L+w)

L+w=178 ➗ 2

L+w=89(1)

W+7=L

L-w=7(11)

L+w=89... (1)

L-w=7(11)

Subtract (11) from (1)

2w=89-7

2w=82

w=82 ➗ 2

w=41 width=41feet

Substitute w=41 in (11)

L-w=7

L-41=7

L=7+41

L=48feet

Area= length x width

Area=48 x 41

Area=1968ft^2

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step-by-step explanation: