PLEEES HELPP!:(. francisco game involves 3 green,2 yellow,4 red. and 3 black marbles. is he randomly draws three marbles from the bag ,without replacement, what is the probability that he will draw yellow, and then red, and then black?

The last choice 1/55

Pr(yellow, red, and black) =  (2/12)*(4/11)*(3/10) = 1/55

Step-by-step explanation:

How many marbles are there total?

3  + 2 + 4 + 3 =  12 total

draw 3 marbles. without replacing

1st marble is yellow, Probability is  2/12

2nd marble is red Probability is 4/11

3rd marble is black Probability is 3/10

the sample space decreases each time we pull a marble.

so the Pr(yellow, red, and black) =  (2/12)*(4/11)*(3/10) = 1/55

i dont know it

step-by-step explanation:

step-by-step explanation:

de-gf

hj=3x+20

ji=15x-64