Find a polynomial equation that has zeros at x = −2, x = 0, x = 3 and x = 5

If a polynomial "contains", in a multiplicative sense, a factor , then the polynomial has a zero at .

So, you polynomial must contain at least the following:

If you multiply them all, you get

Now, if you want the polynomial to be zero only and exactly at the four points you've given, you can choose every polynomial that is a multiple (numerically speaking) of this one. For example, you can multiply it by 2, 3, or -14.

If you want the polynomial to be zero at least at the four points you've given, you can multiply the given polynomial by every other function.

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

if the probability is 1/12, 75 people will receive a $25 gift card

step-by-step explanation: