Can anyone help me solve this question

(6, 3 )

Step-by-step explanation:

Given the 2 equations

5x - y = 27 → (1)

5x + 4y = 42 → (2)

Multiplying (1) by - 1 and adding to (2) will eliminate the x- term, that is

- 5x + y = - 27 → (3)

Add (2) and (3) term by term to eliminate the x- term

5y = 15 ( divide both sides by 5 )

y = 3

Substitute y = 3 into either of the 2 equations and solve for x

Substituting into (2)

5x + 4(3) = 42

5x + 12 = 42 ( subtract 12 from both sides )

5x = 30 ( divide both sides by 5 )

x = 6

Solution is (6, 3 )

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)  

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)