Can u guys PLEASE ANSWER this question ASAP
solve the simultaneous equations using the substitution method

3x+4y=11 and 7x-2y=3

In order to solve using substitution, we'll need to first isolate one variable in one equation. I will be using 7x - 2y = 3 and solving for y to begin.

7x - 2y = 3

-2y = -7x + 3

2y = 7x - 3

y = 3.5x - 1.5

Next, we'll plug in our value of y (found above) into the equation 3x + 4y = 11 and solve for x.

3x + 4(3.5x - 1.5) = 11

3x + 14x - 6 = 11

17x = 17

x = 1

Finally, we'll plug our value of x in to the first equation (7x - 2y = 3) and solve for y.

7(1) - 2y = 3

7 - 2y = 3

-2y = -4

y = 2

The solution to these equations is (1, 2).

Hope this helps! :)

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."