Which term of the sequence –3, 1, 5, 9, 13, … is 65? Alisha solved the question as shown below. an = 65 a1 = –3 d = –3 – 1 = –4 65 = –3 + (n–1)(–4) 65 = –3 –4n + 4 65 = 1 – 4n 65–1 = 4n n = 64 ÷ 4 n = 16 So, the 16th term of the sequence is 65. What is the error in the computation? Find the correct answer.