If the diameter of a nickel is 0.835 in and the width of each nickel is 0.077 in what is the approximate surface area of the 2$ roll of nickels round your answer to the nearest hundredth

Step-by-step explanation:

The roll of nickels forms a cylinder

cylinder area includes the sides and the round areas

round areas  = pi r^2   there is two   so    2 pi r^2

                                                                    = 2 pi (.835/2)^2

and the side area  pi x d x h

                               pi x .835 ( .077 x 40)     (there are 40 nickels in $ 2

Add the areas to get the total

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