Obtain the center for the circle of curvature (osculating circle) for a general point P(x, y) on the ellipse 4x2+9y2=36. Obtain the equation of the circle of curvature for the point P(3,0) on the above ellipse. By parameterizing the ellipse with the variable t where t is the time, obtain the tangential and normal components of acceleration at the point P(x, y).

could you reply to this with the question so i can ?

step-by-step explanation:

f(gx)=f(1/x+2)

=(1/x+2)+2

=(1+2x)/2+2

=(1+2x+4)/2

= (2x+5)/2

and?

step-by-step explanation:

45.36 feet per second.

step-by-step explanation:

to find the most accurate determination for the number of feet per second tyrone traveled on his way to work let us convert miles to feet and minutes to seconds.

1 mile = 5280 feet.

1 minute = 60 seconds.

now we will divide 158400 by 3492 to find the most accurate determination for the number of feet per second tyrone traveled on his way to work.

therefore, tyrone traveled on his way to work at the rate of 45.36 feet per second.