Two dice are tossed (with 6 faces each) at the same time. Define the outcomes X1=’ result from dice #1’ and X2=’ result from dice #2’. Now, consider M= X1-X2 , where M is given by the difference between the outcomes. a) What is the probability that M is negative ? b) What is the probability that M is positive ? c) What is the probability that M=0 ? d) If X2=1 what is the probability that M=6 ? e) If M=1 what is the probability that X1=6 ?

Step-by-step explanation:

The pairs of the Outcome from the two dice are given below:

Given , the sample space of M is:

(a)Probability that M is negative

n(Negative Terms)=15

(b)Probability that M is positive

n(Positive Terms)=15

(c)Probability that M=0

n(Zeroes)=6

(d) n(M=6)=0

(e)If M=1, the probability that

When , the number of outcomes where M=1 is 1.

Therefore:

24+x=y

step-by-step explanation:

so, converting firstly the mixed fractions to improper fractions and then "adding".