subject
Mathematics, 05.05.2020 04:03 sosa1k18

Using the lengths (in.), chest sizes (in.), and weights (lb) of bears from a data set, the resulting regression equation is Weightequalsminus274plus0.426 Lengthplus12.1 Chest Size. The P-value is 0.000 and the adjusted Rsquared value is 0.925. If an additional predictor variable of neck size (in.) is included, the P-value becomes 0.000 and the adjusted Rsquared becomes 0.933. Why is it better to use values of adjusted Rsquared instead of simply using values of Rsquared?

ansver
Answers: 2

Another question on Mathematics

question
Mathematics, 21.06.2019 16:00
Julia is going for a walk through the neighborhood. what unit of measure is most appropriate to describe the distance she walks?
Answers: 1
question
Mathematics, 21.06.2019 19:00
Solving systems of linear equations: tables represent two linear functions in a systemöwhat is the solution to this system? 0 (10)0 (1.6)0 18,26)0 18-22)
Answers: 1
question
Mathematics, 21.06.2019 20:00
Evaluate the discriminant of each equation. tell how many solutions each equation has and whether the solutions are real or imaginary. x^2 - 4x - 5 = 0
Answers: 2
question
Mathematics, 21.06.2019 21:00
Solve this problem! extra ! 3025/5.5 = a/90.75 / = fraction
Answers: 3
You know the right answer?
Using the lengths (in.), chest sizes (in.), and weights (lb) of bears from a data set, the resulting...
Questions
question
Mathematics, 05.03.2020 02:47
question
Social Studies, 05.03.2020 02:49
Questions on the website: 13722359