Mathematics, 05.05.2020 04:26 bommers144

A sector Whos radius is 10 feet, has an area of 200pi/9 ft squared. What are the measures of the central and inscribed angels for this sector?

Answers: 3

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Answer from: holaadios222lol

$\theta=\dfrac{4\pi}{9}$ .

Step-by-step explanation:

Given information:

Radius = 10 feet

Area = $\frac{200\pi}{9}$ sq. ft. ...(i)

We need to find the measures of the central and inscribed angels for this sector.

The area of a sector is

$A=\dfrac{1}{2}r^2\theta$

where, r is radius and $\theta$ is central angle in radian.

Substitute r = 10 in the above formula.

$A=\dfrac{1}{2}(10)^2\theta$

$A=50\theta$ ...(ii)

From (i) and (ii), we get

$50 \theta=\dfrac{200\pi}{9}$

$\theta=\dfrac{200\pi}{9\times 50}$

$\theta=\dfrac{4\pi}{9}$

Therefore, the measure of central angle is $\dfrac{4\pi}{9}$ .

Answer from: Quest

60°

step-by-step explanation:

the measure angle of c in an isosceles triangle abc is 60° because in isosceles triangle,the measures of all the angles is 60°.

Answer from: Quest

x= 1

step-by-step explanation: convert 5\frac{11}{12}5

to improper fraction. use this rule: a \frac{b}{c}=\frac{ac+b}{c}a

ac+b

3.25+0.5x+1\frac{1}{3}+\frac{5}{6}x=\frac{5\times 12+11}{12}3.25+0.5x+1

5×12+11

2 simplify 5\times 125×12 to 6060

3.25+0.5x+1\frac{1}{3}+\frac{5}{6}x=\frac{60+11}{12}3.25+0.5x+1

60+11

3 simplify 60+1160+11 to 7171

3.25+0.5x+1\frac{1}{3}+\frac{5}{6}x=\frac{71}{12}3.25+0.5x+1

4 simplify \frac{5}{6}x

x to \frac{5x}{6}

3.25+0.5x+1\frac{1}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+1

5 convert 1\frac{1}{3}1

to improper fraction. use this rule: a \frac{b}{c}=\frac{ac+b}{c}a

ac+b

3.25+0.5x+\frac{1\times 3+1}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+

1×3+1

6 simplify 1\times 31×3 to 33

3.25+0.5x+\frac{3+1}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+

3+1

7 simplify 3+13+1 to 44

3.25+0.5x+\frac{4}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+

8 simplify 3.25+0.5x+\frac{4}{3}+\frac{5x}{6}3.25+0.5x+

to \frac{13.75}{3}+\frac{4x}{3}

13.75

\frac{13.75}{3}+\frac{4x}{3}=\frac{71}{12}

13.75

9 simplify \frac{13.75}{3}

13.75

to 4.5833334.583333

4.583333+\frac{4x}{3}=\frac{71}{12}4.583333+

10 subtract 4.5833334.583333 from both sides

\frac{4x}{3}=\frac{71}{12}-4.583333

−4.583333

11 simplify \frac{71}{12}-4.583333

−4.583333 to \frac{4}{3}

\frac{4x}{3}=\frac{4}{3}

12 multiply both sides by 33

4x=\frac{4}{3}\times 34x=

×3

13 simplify \frac{4}{3}\times 3

×3 to \frac{12}{3}

4x=\frac{12}{3}4x=

14 simplify \frac{12}{3}

to 44

4x=44x=4

15 divide both sides by 44

x=1

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A sector Whos radius is 10 feet, has an area of 200pi/9 ft squared. What are the measures of the cen...

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