When 10x^3+mx^2- x+10 is divided by 5x-3, the quotient is 2x^2+no-2 and the remainder is 4. what is the value of m and n?

When is divided by, the quotient is and the remainder is 4.

The value of m=-21 and n=-3

Given :

When is divided by, the quotient is and the remainder is 4.

We frame equation using quotient and remainder

Dividend = quotient (divisor)+ remainder

Now we make x^2 parts are equal and solve for m  and n

Also we make x parts are equal

Now make x^2 terms equal

The value of m  and n are

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