∆XYZ has vertices X(0, 3), Y(2, 0), and Z(4, 2). If you reflect ∆XYZ across the line x = 4, what will be the coordinates of the vertices of the image ∆X′Y′Z′?

A.) X′(4, 3), Y′(6, 0), and Z′(4, 2)

B.) X′(3, 0), Y′(0, 2), and Z′(2, 4)

C.) X′(4, 3), Y′(2, 0), and Z′(4, 2)

D.) X′(8, 3), Y′(6, 0), and Z′(4, 2)

D

Step-by-step explanation

Since we are reflecting across the x axis, all of the y coordinates will remain the same. You find the distance away from the x = 4, double it, and add that value to x. So,

X' is now (8,3)

Y' is now  (6,0)

Z' is now (4,2) because its x was 0, and anything * 0 = 0 so it does not move.

answer: a

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