Find the Area of the figure below, composed of an isoceles trapezoid and one
semicircle. Rounded to the nearest tenths place

the total area is 15.6 square units

Step-by-step explanation:

hello,

you can  find the total area  dividing the shape into two known shapes

total area= area of the trapezoid +area of the semicircle

then          

step one

find the area of the isosceles trapezoid using

where

a is the smaller base

b is the bigger base

h is theheight

A is the area

let

a=2

b=5

h=4

put the values into the equation

Step two

find the area of the semicircle

the area of a circle is given by

but, we need the area of  half circle, we need divide this by 2

now the diameter of the semicircle is 2, put this value into the equation

find the total area

total area= area of the trapezoid +area of the semicircle

so, the total area is 15.6 square units

Have a good day.

i think the answer is b)

step-by-step explanation:

last option

step-by-step explanation:

given that δdef is right and isoceles,

assuming that side df is the hypotenuse means that de an ef are the other 2 sides that intersect at 90° and are of equal length.

because they are of equal length, we can say that they are congruent

because they intersect at 90°, their slopes must be opposite reciprocals.

only the last option satisfies these conditions.