Identify the graph of the equation. Then find to the nearest degree.
2x2 + 4xy + 4y2 = 0

This represent a single point (0, 0)  in the real plane.

This is a complex graph x = i*y  - y,   there are imaginary numbers.

Step-by-step explanation:

2 xx + 4xy +  4yy = 0

...xx + 2xy + y*y  + yy = 0

(x + y)^2  + yy = 0

if  x is a constant

then the cross sections would be parabolas in the zy-plane

... 2yy + 4xy  - 2xy  + xx = 0

(2yy + 4xy + 2xx -2xx) - 2xy + xx = 0

2(y + x)^2 - 2xx - 2xy + xx = 0

2(y + x)^2 - xx - 2xy  = 0

2(y + x)^2 - xx - 2xy  +yy  - yy = 0

...

(x + y)^2  + yy = 0

x = i*y  - y

if  x = r cos a

y = r sin a

cos a )^2  + cos a sina  + sin a)^2  +  sin a)^2 = 0

cos a sin a + sin a)^2 = -1

1)is not similar since corresponding sides are not in the same ratio

2)are similar since corresponding sides are in the same ratio and corresponding angles are equal

hope it will

#faazmessi

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3