Mark rolls 2 fair dice and adds the results from each.
Work out the probability of getting a total that is a factor of 18.

1/3

Step-by-step explanation:

The sample space for two dice is given as:

The Sample space for the total of each pair is:

Total Sample Space, n(S)=36

Factors of 18 are 1,2,3,6,9 and 18

Let Event A be the event that the total of each pair is a factor of 18.

Sample Space of A is:

n(A)=12

Therefore, the probability of A

P(A)=n(A)/n(S)=12/36=1/3

The probability of getting a total that is a factor of 18 is One-Third.

just do 5.2 + 2 ( 7.2) and 1/3 x 3 (.9) and youv'e got your equation. 0.9( 9/10) + 7.2 ^2 = 16.4 hope i could !

step-by-step explanation:

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step-by-step explanation: