SOLVE IT! IT MUST BE EGAL WITH ,,1".
I need step by step explain

x = 0

Step-by-step explanation:

-[(3^x - 1)(5^x - 1)] + 1 = 1

Subtract 1 form both sides

-[(3^x - 1)(5^x - 1)] = 0

Divide both sides by -1

(3^x - 1)(5^x - 1) = 0

Equate the factors to 0

3^x - 1 = 0

3^x = 1

Use ln both sides

ln(3^x) = ln(1)

xln(3) = 0

x = 0

5^x - 1 = 0

5^x = 1

Use ln both sides

ln(5^x) = ln(1)

xln(5) = 0

x = 0

The only solution is x = 0

divide the numbers

step-by-step explanation: