A projectile is launched upward with a velocity of 64 feet per second from the top of a 45-foot platform. What is the maximum height attained by the projectile?
height function

Step-by-step explanation:

xf=xo+vot+1/2 g t^2

xo=45 f    vo=64 f/s   g = -32.2 ft/s^2

h(t) = -16.1 t^2 + 64t +45        parobola max will be at t = -b/2a

              -64/(2(-16.1) =1.987 sec = tmax

-16.1(1.987^2)+64(1.987)+45 = 108.6 ft

you need to add a picture

what are you doing do you need examples of variable questions?

step-by-step explanation:

5a-1=9               bring the one over the =

5a=10                     divide by your variable

a=2

brainliest? ?

here try this one

3a-24=0