The three seventh grade classes at Sunview Middle School collected the most box tops for a school fundraiser, and so they won a $600 prize to share among them. Mr. Aceves class collected 3,760 box tops, Mrs. Baca´s class collected 2,301 and Mr. Canyonś class collected 1,855. How should they divide the money so that each class gets the same fraction of the prize money as the fraction of the box tops that they collected?

First, find the total amount of box tops:
3760 + 2301 + 1855 = 7916

Next find the percent that Mr Aceves class contributed:
3760/7916 = about .47 or 47 percent.

The percent Mrs Bacas class contributed:
2301/7916 = about .29 or 29 percent

The percent Mr Canyons class contributed:
1855/7916 = about .23 or 23 percent.

After, find 47 percent of $600, because Mr Aceves class contributed 47 percent of the total box tops.
.47 * 600 = $282

Next find 29 percent of $600, because Mrs Bacas class contributed 29 percent of the total box tops.
.29 * 600 = $174

Lastly find 23 percent of $600, because Mr Canyons class contributed 23 percent of the total box tops.
.23* 600 = $138

Do the inverse operation