A transit company charges $1.25 per ride and currently averages 27,500 riders per day. The company needs to increase revenue but found that for each $0.10 increase in fare the company would lose 1000 riders. What should the company charge to maximize revenues?

Charge the additional $0.10 even if you loose 1000 riders

Step-by-step explanation:

Original:

27,500 x $1.25 = $34,375

Charge additional $0.10 but loose 1000 riders:

(27,500 - 1000) x ($1.25 + $0.10)

26,500 x $1.35 = $35,775

you are saying it as if a fact, not a question, but yes, you would be correct? ; )

step-by-step explanation:

he used the algebra tiles correctly.

step-by-step explanation:

given : 3x(2x-1)

solution :

since he used algebra tiles .

armando's solution is the same in the solution shown in figure

as he distributed 2x into x and x and wrote them vertically

and also write   -1 vertically

and 3x into x and x and x and wrote it horizontally

performing the multiplication in the algebra tiles we get

and solving the given expression :

3x(2x-1)

since solving the expression using tiles   and solving the expression algebraically we get the same answer

thus   we can choose the first statement as the answer to this problem which is "he used the algebra tiles correctly".