What is the value of x?

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A triangle with midsegment parallel to the base. the left side is labeled 72 cm below the midsegment and 9 cm above the midsegment. the right side is labeled 56 cm below the midsegment and 3 x minus 20 above the midsegment.

nada

step-by-step explanation:

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

answ5

step-by-step explanation:

u have to pay atttion to me

i'm sorry mate, but i am not seeing any figures. i am unable to solve this for you.