A regular type of laminate is currently being used by a manufacturer of circuit boards. A special laminate has been developed to reduce the warpage. The regular laminate will be used on one sample of specimens and the special laminate on another sample, and the amount of warpage will then be determined for each specimen. The manufacturer will then switch to the special laminate only if it can be demonstrated that the true average amount of warpage for that laminate is less than for the regular laminate. State the relevant hypotheses.
a. H0: μregular > μspecial
b. Ha: μregular = μspecialH0: μregular = μspecial
c. Ha: μregular < μspecial H0: μregular = μspecial
d. Ha: μregular > μspecialH0: μregular = μspecial
e. Ha: μregular

The correct option is (d).

Step-by-step explanation:

It is provided that a special laminate has been developed to reduce the warpage.

The will then switch to the special laminate only if it can be demonstrated that the true average amount of warpage for that laminate is less than for the regular laminate.

To determine whether he should switch tot he special type of laminate or not, the manufacturer uses the regular laminate on one sample of specimens and the special laminate on another sample, and the amount of warpage will then be determined for each specimen.

The hypothesis for this test can be defined as follows:

H₀: The true average amount of warpage for special type of laminate is same as that for the regular laminate, i.e.

Hₐ: The true average amount of warpage for special type of laminate is less than for the regular laminate, i.e.

Thus, the relevant hypotheses is defined by (d).

A circuit board producer is now using a standardized sort of lamination. To reduce warpage, a special laminate was developed. A conventional laminate will be applied to one collection of the specimens.

Specify the hypothesis at issue.

Therefore, the final answer is "Option D".

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graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.