Will give What is the relationship between the sine and cosine of complementary angles in a right triangle? Please give an example to support your answer.

they are equal

Step-by-step explanation:

Consider the right triangle ABC with sides a, b, and c as shown in the figure.  

Let m(\angle A)=\alpha, and m(\angle B)=\beta.

\alpha +\beta=90^{\circ}, so angles A and B are complementary.

According to the definition of sine, and cosine:

\displaystyle{ \sin \alpha= \frac{opposite\ side}{hypotenuse} =\frac{a}{c} , and

\displaystyle{ \cos \beta= \frac{adjacent\ side}{hypotenuse} =\frac{a}{c}  

this is a very good question

step-by-step explanation:

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the answer will be b x² +x-1

step-by-step explanation: