Given the functions f(n) = 25 and g(n) = 3(n − 1), combine them to create an arithmetic sequence, an, and solve for the 12th term.

An arithmetic sequence can be defined using the first term f(n) and the common difference in the g(n) term. In this case, we have:
a(n) = f(n) + g(n) = 25 + 3(n-1) = 3n + 22
If we want to find the 12th term, we substitute n = 12 into a(n):
a(12) = 3(12) + 22 = 36 + 22 = 58