M = 12x 201
my 121
we
(+1) = 12 (0-1) i find a
have (n+1)! = 12 (n-1)
(211) (n+1-1) (+)-2)! = 1
(n+1)(u)(n-1)) = 12 (nel)
(n²th) = 120
(2)!

What the heck i didn’t know

The question is kind of confusing. if it's asking how many variations of answers can you give. then do 4^5 for your answer.this would be something like the first question could be a and the 2nd c or first b next c etc. if you can, ask the teacher for a better confirmation of what it's asking. if i'm assuming correctly what it's asking, it's 625 different variations.