What is the height of the triangular base of the pyramid?

9 √ 2 in.
9 √ 3 in.
18 √ 2 in.
18 √ 3 in.

Please consider the complete question.

The base of a solid oblique pyramid is an equilateral triangle with a base edge length of 18 inches. What is the height of the triangular base of the pyramid?

First of all, we will draw an equilateral triangle.

Since the given triangle is equilateral triangle, so all sides will have same length that is 18 inches.

We know that height of an equilateral triangle is , where a is side length of equilateral triangle.

Therefore, the height of the given equilateral triangular base will be inches and option B is the correct choice.

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

total of apples - take away four

6-4 = 2

answer is 2 apples