Solve the problem.

Find the length of a rectangular lot with a perimeter of 108 m if the length is 8 m more than the width.

A.54 m

B.31 m

C.62 m

D.23 m

B 31m

Step-by-step explanation:

31-8=23

2(31+23)=108

d) 30 units^2

area of rectangle = l × b

we know,

length = 10 unit

breadth = 3 unit

applying the formula,

= l × b

= 10 × 3

= 30 unit^2

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