A baker puts 5 cups of fruit into each pie he bakes. he pays $0.75 for 1 cup of fruit and $2.50 for the pie crust. He sells each pie for $10.25. After subtracting the cost of the fruit and pie crust, how much does he earn if he sells 10 pies?

He earn $40

Step-by-step explanation:

To solve this problem, we first have to calculate how much it spends to make each pie

cups of fruit = 5

5 * $0.75 = $3.75

This means that per pie he spends $ 3.75 on cups of fruit and $ 2.50 on  pie crust

If we add them together we will get how much he spends for each pie

$3.75 + $2.50 = $6.25

Now to the price that the pie sells we subtract this value to know how much you earn for each pie

$10.25 - $6.25 = $4

if he sold 10 pies we multiply this number by 10 and we will get his total profit

$4 * 10 = $40

He earn $40

there are lots of ways.   pick's theorem tells us if the vertices are lattice points the area a is

a = b/2 + i - 1

where b is the number of boundary lattice points and i is the number of interior lattice points.

in the figure i count b=16, i=50 so

a = 8 + 50 - 1 = 57

let's try the shoelace formula.   the area is half the sum of the cross products of the sides.  

a(-2,6)   -2(2)-6(-5) = 26

b(-5,2)   -5(-3) - 2(-2) = 19

c(-2,-3) -2(-3) - (-3)(4) = 18

d(4,-3)   4(3) - (-3)(5) = 27

e(5,3)   5(3) - 3(1) = 12

f(1,3)     1(6) - 3(-2) = 12

a(-2,6)

each of the cross products is twice the area of the triangle with the associated side and one vertex the origin. so the area of abo=26/2=13.

area = (1/2) (26 + 19 +   18 + 27 + 12 + 12) = 57

that checks!

he spend 5.1 minutes chatting with his friends

step-by-step explanation:

2/5+1/2=9/10

6/1-9/10=5 1/10