An object is launched from a platform.
Its height (in meters), x seconds after the launch, is modeled by
h(x)=-5(x+1)(x-9)h(x)=−5(x+1)(x−9)h
What is the height of the object at the time of launch?
This question is from Khan Academy.

the answer is. -82562234434584

step-by-step explanation:

30 people weigh 160 pounds or more

whats the rest of it?

part a: triangles gcb and epb

part b. sides cg and rp are parallel by definition of parallelogram.

angles cgb and e are congruent by being alternate interior angles of parallel lines cut by a transversal. angles gbc and ebp are congruent because they are vertical angles. by aa similarity, the triangles are similar.

part c. since the triangles are similar, the ratios of the lengths of corresponding sides are equal.

calculation of be:

gb/be = cb/bp

(400 ft)/be = 300/200

(400 ft)/be = 3/2

3be = 2 * 400 ft

3be = 800 ft

be = 800/3 ft

calculation of pe:

gc/pe = cb/bp

(350 ft)/pe = 300/200

(350 ft)/pe = 3/2

3pe = 2 * 350 ft

3pe = 700 ft

pe = 700/3 ft