Solve 2(a + 7) = 5a - 13

a = 9

Step-by-step explanation:

2(a + 7) = 5a - 13

We want to bring a to one side, I will choose to bring it to the right

First, expand the bracket by multiplying 2 with a + 7

2a + 14 = 5a - 13

Bring the -13 to the left by adding 13 to both sides

2a + 14 + 13 = 5a - 13 + 13

Simplify

2a + 27 = 5a

Bring the 2a to the right by subtracting 2a from both sides

2a - 2a + 27 = 5a - 2a

Simplify

27 = 5a - 2a

27 = 3a

Bring the 3 to the left by dividing both sides by 3

27÷3 = a

Simplify

a = 9

i'm not entirely sure

step-by-step explanation:

if you ask home depot or lowe's they might be able to you out

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.