Assume that you have a sample of n 1 equals 6, with the sample mean Upper X overbar 1 equals 50, and a sample standard deviation of Upper S 1 equals 7, and you have an independent sample of n 2 equals 5 from another population with a sample mean of Upper X overbar 2 equals 38 and the sample standard deviation Upper S 2 equals 8. Assuming the population variances are equal, at the 0.01 level of significance, is there evidence that mu 1 greater than mu 2?

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

Step-by-step explanation:

Data given

represent the sample size for group 1

represent the sample size for group 2

represent the sample mean for the group 1

represent the sample mean for the group 2

represent the sample standard deviation for group 1

represent the sample standard deviation for group 2

System of hypothesis

The system of hypothesis on this case are:

Null hypothesis:

Alternative hypothesis:

We are assuming that the population variances for each group are the same

The statistic for this case is given by:

The pooled variance is:

We can find the pooled variance:

And the pooled deviation is:

The statistic is given by:

The degrees of freedom are given by:

The p value is given by:

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

180

step-by-step explanation:

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°