11. Get slotMachine numbers for slotMachines played at any casino by a player from the same city as that casino. 12. Name the casinos that have been visited by at least one player who is not from the same city as that casino. 13. Get all pairs of slotMachine numbers such that some player has played both the indicated slotMachines. 14. Get the total number of casinos that have been visited by player P50. 15. Get the total amount of totalBets for player P10 on slotMachine S100. 16. For each slotMachine in a casino, get the slotMachine number, the casino number, and the sum of the totalBets (for that slotMachine at that casino). 17. Get slotMachine numbers of slotMachines with an average TotalBet of more than 320. 18. Name the casinos that have been visited by Sheldon. 19. Get the denominations of slotMachines played by Sheldon. 20. Name the slotMachines located in any casino in LasVegas.

quit

step-by-step explanation:

coins of silver or gold

step-by-step explanation:

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.

irst, find the z score of a score of 80. this is given by the formula z = (x-u)/o, where x is the score, u is the mean, and o is the standard deviation. this gives

z = (80-78)/12 = 1/6 = .1667

now, find what percentile a z score of 1/6 correlates to in the normal distribution.

a z score of 1/6 = .1667 is equivalent to the 56.36th percentile of the distribution. so the probability a score is over this is 1-.5636 = .4364

the mean of a sample mean is equal to the original mean. however, the standard deviation of a sample mean is equal to the original standard deviation divided by the square root of n (sample size). so the new standard deviation is 12/sqrt(16) = 3.

the new z score is 80-78/3 = 2/3 = .667. this is equivalent to the 74.86th percentile. so the probability that the mean will be greater than this score is 1-.7486 = .2514.