In ΔDEF, the measure of ∠F=90°, the measure of ∠D=19°, and DE = 40 feet. Find the length of EF to the nearest tenth of a foot.

13.0feet

Step-by-step explanation:

Given ΔDEF with ∠F=90°, the measure of ∠D=19°, and DE = 40 feet, since one of the angles of the triangle is 90°, the triangle is a right angled triangle as shown in the attachment.

Using SOH, CAH, TOA to get the unknown EF.

Since <D is opposite to side EF, EF will be the opposite while side DE will be the hypotenuse

Based on SOH:

Sin<D = Opposite/Hypotenuse

Sin<D = EF/DE

Sin19° = EF/40

EF = 40sin19°

EF = 13.0 feet to the nearest tenth of a foot

3, 12, 48, 384, 1536, 6144, 24576, 98304

step-by-step explanation:

just keep timing it by 4.

first, you divide the triangle in two, tô form a retangle triangle. after, using pythagoream theorem:

18^2 = 14^2 + (x/2)^2

(x^2/4) + 196 = 324

x^2/4 = 324 - 196

x^2/4 = 128

x^2 = 512

x = √512

x = √2^9

x = 16√2 cm

i hope i you.